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离开某个特定日子的时间

稿源：互联网 2022-04-16 07:46:47 点击： 374 撤稿纠错

一个时间统计脚本，计算离开某个日子的时间，可自定义指定日期。

以下讨论的是和特效相关的离开某个特定日子的时间教程文章，内容是本站精心挑选整理的教程，希望对广大的网友给到帮助,下面是详细内容：

脚本代码(For Alixixi.com)如下:

<!--要完成此特效需要两个步骤

第一步：把如下代码加入到<body>区域中-->

<!--

var timerID;

var timerRunning = false;

var today = new Date();

var startday = new Date();

var secPerDay = 0;

var minPerDay = 0;

var hourPerDay = 0;

var secsLeft = 0;

var secsRound = 0;

var secsRemain = 0;

var minLeft = 0;

var minRound = 0;

var minRemain = 0;

var timeRemain = 0;

/* This function will stop the clock */

function stopclock()

{

if(timerRunning)

clearTimeout(timerID);

timerRunning = false;

}

/* This function will start the clock */

function startclock()

{

stopclock();

showtime1();

}

/* This function will display the count-up */

function showtime1()

{

startday = new Date("July 20, 1969 16:18 EDT");

startday.setYear("1969");

today = new Date();

secsPerDay = 1000 ;

minPerDay = 60 * 1000 ;

hoursPerDay = 60 * 60 * 1000;

PerDay = 24 * 60 * 60 * 1000;

/* Seconds */

secsLeft = (today.getTime() - startday.getTime()) / minPerDay;

secsRound = Math.round(secsLeft);

secsRemain = secsLeft - secsRound;

secsRemain = (secsRemain < 0) ? secsRemain = 60 - ((secsRound - secsLeft) * 60) :

secsRemain = (secsLeft - secsRound) * 60;

secsRemain = Math.round(secsRemain);

/* Minutes */

minLeft = ((today.getTime() - startday.getTime()) / hoursPerDay);

minRound = Math.round(minLeft);

minRemain = minLeft - minRound;

minRemain = (minRemain < 0) ? minRemain = 60 - ((minRound - minLeft) * 60) : minRemain =

((minLeft - minRound) * 60);

minRemain = Math.round(minRemain - 0.495);

/* Hours */

hoursLeft = ((today.getTime() - startday.getTime()) / PerDay);

hoursRound = Math.round(hoursLeft);

hoursRemain = hoursLeft - hoursRound;

hoursRemain = (hoursRemain < 0) ? hoursRemain = 24 - ((hoursRound - hoursLeft) * 24)  :

hoursRemain = ((hoursLeft - hoursRound) * 24);

hoursRemain = Math.round(hoursRemain - 0.5);

/* Days */

daysLeft = ((today.getTime() - startday.getTime()) / PerDay);

daysLeft = (daysLeft - 0.5);

daysRound = Math.round(daysLeft);

daysRemain = daysRound;

/* Time */

if (daysRemain == 1)

{

day_rem = " 天, "

}

else

{

day_rem = " 天, "

}

if (hoursRemain == 1)

{

hour_rem = " 小时, "

}

else

{

hour_rem = " 小时, "

}

if (minRemain == 1)

{

min_rem = " 分, "

}

else

{

min_rem = " 分, "

}

if (secsRemain == 1)

{

sec_rem = " 秒"

}

else

{

sec_rem = " 秒"

}

timeRemain = daysRemain + day_rem + hoursRemain + hour_rem + minRemain +

min_rem + secsRemain + sec_rem;

document.up.face.value = timeRemain;

timerID = setTimeout("showtime1()",1000);

timerRunning = true;

}

//-->

</SCRIPT>

</FORM>

<P>

<FONT SIZE=+1 FACE="Arial">离开人类登月已经

</FONT>

<body onLoad="startclock()">
<a href="http://www.alixixi.com/Dev/HTML/jsrun/">欢迎访问阿里西西网页特效集</a>

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离开某个特定日子的时间

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